7+42*3^(2-3a)=14*3^(2-3a)+7

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Solution for 7+42*3^(2-3a)=14*3^(2-3a)+7 equation: 



7+42*3^(2-3a)=14*3^(2-3a)+7

We move all terms to the left:

7+42*3^(2-3a)-(14*3^(2-3a)+7)=0

We add all the numbers together, and all the variables

42*3^(-3a+2)-(14*3^(-3a+2)+7)+7=0

Wy multiply elements

126a(--(14*3^(-3a+2)+7)+7=0

We use the square of the difference formula

126a(+(14*3^(-3a+2)+7)+7=0

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